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Originally posted by: stonysmithDid the error message include a line #?
It's likely that the error is one of these 3 lines:
Server=s[4]
Graph=s[6]
User=s[5]
If FileName does not include all three pieces you're looking for, the error could be coming from there.
You may need to filter out some filenames before you try to parse it this way, or use this:
s=split(FileName+"//////","/")